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Question: A block of mass in and charge q is placed on a smooth horizontal table which terminates in a vertica...

A block of mass in and charge q is placed on a smooth horizontal table which terminates in a vertical wall at a distance d the block . A horizontal electric field E towards right is switched on. Assuming elastic collision, find time period of the resulting oscillatory motion.

A

8dmqE\sqrt{\frac{8dm}{qE}}

B

4dmqE\sqrt{\frac{4dm}{qE}}

C

2dmqE\sqrt{\frac{2dm}{qE}}

D

None of these

Answer

8dmqE\sqrt{\frac{8dm}{qE}}

Explanation

Solution

a = qE/m and d = 1/2 at2

or t = 2da=2dmqE\sqrt{\frac{2d}{a}} = \sqrt{\frac{2dm}{qE}}

Time period T = 2t = 22dmqE\sqrt{\frac{2dm}{qE}} = 8dmqE\sqrt{\frac{8dm}{qE}}