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Question

Physics Question on Work-energy theorem

A block of mass 5kg5 kg moves along the xx-direction subject to the force F=(20x+10)N,F = (−20x + 10) N, with the value of xx in metre. At time t=0s,t = 0 s, it is at rest at position x=1mx = 1 m. The position and momentum of the block at t=(π/4)t = (\pi/4) s are

A

0.5m,5kg ms-0.5m,5kg \ \frac{m}{s}

B

0.5m,0kg ms0.5m,0kg \ \frac{m}{s}

C

0.5m,0kg ms0.5m,0kg \ \frac{m}{s}

D

0.5m,0kg ms0.5m,0kg \ \frac{m}{s}

Answer

0.5m,0kg ms0.5m,0kg \ \frac{m}{s}

Explanation

Solution

The correct option is (C):0.5m,0kg ms0.5m,0kg \ \frac{m}{s}