Question

A block of mass $5\, kg$ is placed at rest on a table of rough surface Now, if a force of $30\, N$ is applied in the direction parallel to surface of the table, the block slides through a distance of $50\, m$ in an interval of time $10 \,s$ Coefficient of kinetic friction is (given, $g =10 \,ms ^{-2}$ ):

• A. 0 .50
• B. $0.60$
• C. $0.75$
• D. $0.25$

Answer 1

Answer: (A)

0 .50

Answer 2

S=ut+21​at2
50=0+21​×a×100
a=1m/s2
F−μmg=ma
30−μ×50=5×1
50μ=25
μ=21​