Question

A block of mass 5 kg is moving horizontally at a speed of 1.5 m/s. A perpendicular force of 5N acts on it for 4 sec. What will be the distance of the block from the point where the force started acting

• A. 10 m
• B. 8 m
• C. 6 m
• D. 2 m

Answer 1

Answer: (A)

10 m

Answer 2

$S _ { \text {Horizontal } } = u t = 1.5 \times 4 = 6 \mathrm {~m}$

$S _ { \text {Vertical } } = \frac { 1 } { 2 } a t ^ { 2 } = \frac { 1 } { 2 } \frac { F } { m } t ^ { 2 } = \frac { 1 } { 2 } \times 1 \times 16 = 8 m$

$S _ { \mathrm { Net } } = \sqrt { 6 ^ { 2 } + 8 ^ { 2 } } = 10 m$