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Question: A block of mass 4 kg is placed across the ceiling of a room as shown. A force F = 100 N is applied a...

A block of mass 4 kg is placed across the ceiling of a room as shown. A force F = 100 N is applied at 370with the horizontal. If the coefficient of kinetic friction between the block and the ceiling is 0.50 then magnitude of acceleration of the block is:

A

17.5 m/s2s

B

15 m/s2

C

20 m/s2

D

25 m/s2

Answer

17.5 m/s2s

Explanation

Solution

For vertical equilibrium

mg + N = F sin 370

N = 60 – 40 = 20 N

For horizontal motion, applying N/L

F cos 370 - μN = ma

⇒ a = 17.5 m/s2