Question

A block of mass 200 g is kept stationary on a smooth inclined plane by applying a minimum horizontal force $F=\sqrt xN$ as shown in figure.

The value of x = ______.

Answer 1

$F cos60° = mg sin60°$

$F=\frac{1}{2}=0.210×\frac{\sqrt3}{2}$

$⇒F=2\sqrt3$

$⇒F=\sqrt {12}N$

$∴ x = 12$