Question

A block of mass 2 kg rest on a plane inclined at an angle of $30^{o}$with the horizontal. The coefficient of friction between the block and the surface is 0.7. What will be the frictional force acting on the block?

• A. 10.3 N
• B. 23.8 N
• C. 11.9 N
• D. 6.3 N

Answer 1

Answer: (C)

11.9 N

Answer 2

Here friction force, $f = \mu R$

$= \mu mg\cos\theta$

$= 0.7 \times 2 \times 9.8\cos 30{^\circ}$

$= 0.7 \times 2 \times 9.8 \times 0.866$

$= 11.9N$