Question

A block of mass 2 kg is kept on the floor. The coefficient of static friction is 0.4. If a force F of 2.5 Newtons is applied on the block as shown in the figure, the frictional force between the block and the floor will be

• A. 2.5 N
• B. 5 N
• C. 7.84 N
• D. 10 N

Answer 1

Answer: (A)

2.5 N

Answer 2

Applied force $= 2.5 \mathrm {~N}$

Limiting friction $= \mu m g = 0.4 \times 2 \times 9.8 = 7.84 \mathrm {~N}$

For the given condition applied force is very smaller than limiting friction.

$\therefore$ Static friction on a body = Applied force = 2.5 N