Question

A block of mass 100 gm is placed on a smooth surface, moves with the acceleration of a=2x, the change in kinetic energy can be given as $(\frac {x^n}{10})$, find the value of n.

Answer 1

The answer is 2

$l$= 20 cm (The spring natural length)
m = given 100 gm
k = 7.5 $\frac{N}{m}$
mw2 ($l +x$)
Kx = mw2 ($l +x$)
x = $\frac{m\omega ^{2}l}{K-m\omega ^{2}}$
$T=Kx=|\frac{m\omega ^{2}lK}{K-m\omega ^{2}}|$
$T=\frac{0.1\times25\times 0.2\times 7.5}{7.5-0.1\times 25}$
$T=\frac{7.5\times0.1\times 5}{5}$
T= 0.75 N