Question

A block of mass 10 kg starts sliding on a surface with an initial velocity of 9.8 ms–1. The coefficient of friction between the surface and block is 0.5. The distance covered by the block before coming to rest is[use g = 9.8 ms–2]

• A. 4.9 m
• B. 9.8 m
• C. 12.5 m
• D. 19.6 m

Answer 1

Answer: (B)

9.8 m

Answer 2

s=$\frac{u^2}{2a}$=$\frac{u^2}{2(μg)}$
$\frac{(9.8)}{2/2×0.5×(9.8)}$
= 9.8 m
The correct option is (B) : 9.8 m