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Question

Physics Question on laws of motion

A block of mass 10kg10\, kg is placed on rough horizontal surface whose coefficient of friction is 0.50.5. If a horizontal force of 100N100 \,N is applied on it, then acceleration of the block will be :-

A

10m/s210\, m/s^{2}

B

5m/s25 \,m/ s^{2}

C

15m/s215 \,m/ s^{2}

D

0.5m/s20.5 \,m/s^{2}

Answer

5m/s25 \,m/ s^{2}

Explanation

Solution

f _{\text{\max }}=\mu N =\mu \,Mg =(0.5)(10)(10)=50 \,N

a= net force  mass \Rightarrow\, a =\frac{\text { net force }}{\text { mass }}
=1005010=\frac{100-50}{10}
=5m/sec2=5\, m / sec ^{2}