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Question: A block of mass 10 kg is placed on a rough horizontal surface having coefficient of friction μ = 0.5...

A block of mass 10 kg is placed on a rough horizontal surface having coefficient of friction μ = 0.5. If a horizontal force of 100 N is acting on it, then acceleration of the block will be

A

0.5 m/s2

B

5 m/s2

C

10 m/s2

D

15 m/s2

Answer

5 m/s2

Explanation

Solution

a= Applied force − Kinetic friction  mass a = \frac { \text { Applied force } - \text { Kinetic friction } } { \text { mass } }

=100−0.5×10×1010=5 m/s2= \frac { 100 - 0.5 \times 10 \times 10 } { 10 } = 5 \mathrm {~m} / \mathrm { s } ^ { 2 }