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Question: A block of mass 10 kg is placed on a rough horizontal surface having coefficient of friction μ = 0.5...

A block of mass 10 kg is placed on a rough horizontal surface having coefficient of friction μ = 0.5. If a horizontal force of 100 N is acting on it, then acceleration of the block will be

A

0.5 m/s2

B

5 m/s2

C

10 m/s2

D

15 m/s2

Answer

5 m/s2

Explanation

Solution

a=Applied force – kineticfrictionmassa = \frac{\text{Applied force }\text{–}\text{ kineticfriction}}{\text{mass}}

=1000.5×10×1010= \frac{100 - 0.5 \times 10 \times 10}{10}

= 5m/s2.