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Question

Physics Question on laws of motion

A block of mass 10kg10\, kg is in contact against the inner wall of a hollow cylindrical drum of radius 1m1\,m. The coefficient of friction between the block and the inner wall of the cylinder is 0.10.1. The minimum angular velocity needed for the cylinder to keep the block stationary when the cylinder is vertical and rotating about its axis, will be :
(g=10 m/s2)(g = 10\ m/s^2)

A

10 rad/s

B

10 π\pi rad/s

C

10 rad/s\sqrt{10} \ rad/s

D

102π\frac{10}{2\pi} rad/s

Answer

10 rad/s

Explanation

Solution

For equilibrium of the block limiting friction
fLmgf_{L} \ge mg
μNmg\Rightarrow \mu N \ge mg
μmrω2mg\Rightarrow \mu mr\omega^{2} \ge mg
ωgrμ\omega \ge \sqrt{\frac{g}{r\mu}}
ωmin=grμ\omega_{min } =\sqrt{\frac{g}{r\mu}}
ωmin=100.1×1=10\omega_{min } = \sqrt{\frac{10}{0.1 \times1}} = 10 rad/s

So, the correct option is (A): 10 rad/s