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Question: A block of mass 1 kg is pushed up a surface inclined to horizontal at an angle of \(30 ^ { \circ }\...

A block of mass 1 kg is pushed up a surface inclined to horizontal at an angle of 3030 ^ { \circ } by a force of 10 N parallel to the inclined surface as shown in the figure.

The coefficient of friction between block and the incline is 0.1. If the block is pushed up by 10 m along the incline, then the work against gravity is :

(Take g=10 ms2\mathrm { g } = 10 \mathrm {~ms} ^ { - 2 })

A

10 J

B

50 J

C

100 J

D

150 J

Answer

50 J

Explanation

Solution

The various forces acting on the block are as shown in the figure.

Here, m=1 kg,θ=30,F=10 N\mathrm { m } = 1 \mathrm {~kg} , \theta = 30 ^ { \circ } , \mathrm { F } = 10 \mathrm {~N}

μ=0.1,d=10 m\mu = 0.1 , d = 10 \mathrm {~m}

Work done against gravity is