Question

A block of mass 0.50 kg is moving with a speed of 2.00 ms^–1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is :

• A. 0.16 J
• B. 1.00 J
• C. 0.67 J
• D. 0.34 J

Answer 1

Answer: (C)

0.67 J

Answer 2

DE = $\frac { 1 } { 2 }$ $\frac{m_{1}m_{2}}{m_{1} + m_{2}}$ (u₁ – u₂)² (1 – e²)

= $\frac{1}{2}$ $\frac{0.5 \times 1}{1.5}$ (2 – 0)² (1 – 0)² = 0.67 J