Question

A block of mass 0.1 kg is held against a wall by applying a horizontal force of 5 N on it. If $\mu,$ between the wall? and the block is 0.5, the magnitude of the frictional force acting on the block is

• A. 0.98 N
• B. 0.49 N
• C. 4.9 N
• D. 2.5 N

Answer 1

Answer: (A)

0.98 N

Answer 2

Refer figure.
Limiting value of frictional force,
$f _{\max }=\mu N =.5 \times 5=2.5 N$
Now, value of $mg =0.1 \times 9.8=0.98 N$
$f _{\max }> mg$
then frictional force acting on block is
$f = mg =0.98 N$