Question

A block of 1 kg is stopped against a wall by applying a force F perpendicular to the wall. If $\mu = 0.2$ then minimum value of F will be

• A. 980 N
• B. 49 N
• C. 98 N
• D. 490 N

Answer 1

Answer: (B)

49 N

Answer 2

$F = \frac{W}{\mu} = \frac{1 \times 9.8}{0.2} = 49N$