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Question: A block moves in a straight line with velocity \( v \) for time \( {t_0} \) .Then, its velocity beco...

A block moves in a straight line with velocity vv for time t0{t_0} .Then, its velocity becomes 2v2v for next t0{t_0} time. Finally, its velocity becomes 3v3v for time TT . If average velocity during the complete journey was 2.5v2.5v , then find TT in terms of t0{t_0} .

Explanation

Solution

Hint : In this solution, we will use the relation of the average velocity of the object as the ratio of the total distance travelled by the objected to the total amount of time taken by the object to cover that distance. By using this relation, we’ll be able to find TT in terms of t0{t_0} .

Formula used: In this solution we will be using the following formula,
Avg. speed = TotaldistanceTotaltime{\text{Avg}}{\text{. speed = }}\dfrac{{{\text{Total}}\,{\text{distance}}}}{{{\text{Total}}\,{\text{time}}}}

Complete step by step answer
We’ve been given that a block moves in a straight line with velocity vv for time t0{t_0} .Then, its velocity becomes 2v2v for next t0{t_0} time. Finally, its velocity becomes 3v3v for time TT . To calculate the average velocity of this block, we need to find the total distance traveled by this block. For the time when the block is moving is with a velocity vv , the distance it will travel in time t0{t_0} will be
d1=vt0{d_1} = v{t_0}
For the next time bracket, when the object is moving with velocity 2v2v , the distance it will cover in t0{t_0} will be
d2=2vt0{d_2} = 2v{t_0}
Similarly, for the last part of its motion, when its velocity is 3v3v , the distance it will cover in time TT will be
d3=3vT{d_3} = 3vT
Then the average velocity of the object can be calculated as the ratio of the distance of the object to the total time taken by the object to travel this distance as:
vavg=d1+d2+d3t0+t0+T{v_{avg}} = \dfrac{{{d_1} + {d_2} + {d_3}}}{{{t_0} + {t_0} + T}}
On placing the values of d1,d2,d3{d_1},{d_2},{d_3} , we get,
vavg=vt0+2vt0+3vT2t0+T{v_{avg}} = \dfrac{{v{t_0} + 2v{t_0} + 3vT}}{{2{t_0} + T}}
vavg=3vt0+3vT2t0+T\Rightarrow {v_{avg}} = \dfrac{{3v{t_0} + 3vT}}{{2{t_0} + T}}
But we’ve been given the average velocity in the question as 2.5v2.5v , so we can say that
2.5v=3vt0+3vT2t0+T2.5v = \dfrac{{3v{t_0} + 3vT}}{{2{t_0} + T}}
Dividing both sides by vv , we get,
2.5=3t0+3T2t0+T2.5 = \dfrac{{3{t_0} + 3T}}{{2{t_0} + T}}
5t0+2.5T=3t0+3T\Rightarrow 5{t_0} + 2.5T = 3{t_0} + 3T
Solving for TT , we get
T=4t0T = 4{t_0}.

Note
Here, we can use this simple relation for average velocity only because the object is moving in a straight line otherwise, we would have to take into account the direction of the object. In such cases, it is always beneficial to find the total distance travelled by the object as the object is moving different distances with different velocities so we can use the total distance it travels to calculate the average velocity.