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Question

Physics Question on laws of motion

A block kept on a rough inclined plane, as shown in the figure, remains at rest upto a maximum force 2N2 \,N down the inclined plane. The maximum external force up the inclined plane that does not move the block is 10N10\, N. The coefficient of static friction between the block and the plane is : [Take g=10m/s2g = 10\, m/s^2]

A

23\frac{2}{3}

B

32\frac{\sqrt{3}}{2}

C

34\frac{\sqrt{3}}{4}

D

12\frac{1}{2}

Answer

32\frac{\sqrt{3}}{2}

Explanation

Solution

2+mgsin30=μmgcos302+m g \sin 30=\mu m g \cos 30^{\circ}
10=mgsin30+μmgcos3010=m g \sin 30+\mu m g \cos 30^{\circ}
=2μmgcos302\quad=2 \mu m g \cos 30-2
6=μmgcos306=\mu m g \cos 30
4=mgsin304=m g \sin 30
32=μ×3\frac{3}{2}=\mu \times \sqrt{3}
μ=32\mu=\frac{\sqrt{3}}{2}