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Question: A block is resting on a horizontal plate in the XY plane and co-efficient of friction between block ...

A block is resting on a horizontal plate in the XY plane and co-efficient of friction between block and the plate is 'm'. The plate begins to move with velocity u = bt2 in X-direction. At what time will the block starts sliding from plate –

A

μbg\frac { \mu b } { g }

B

μbg2\frac { \mu b g } { 2 }

C

μgb\frac { \mu \mathrm { g } } { \mathrm { b } }

D

μg2 b\frac { \mu \mathrm { g } } { 2 \mathrm {~b} }

Answer

μg2 b\frac { \mu \mathrm { g } } { 2 \mathrm {~b} }

Explanation

Solution

m mg = m. 2bt ̃ t = μg2 b\frac { \mu \mathrm { g } } { 2 \mathrm {~b} }