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Question: A block is placed on an inclined plane moving towards right horizontally with an acceleration a<sub>...

A block is placed on an inclined plane moving towards right horizontally with an acceleration a0 = g.The length of the plane AC = 1 m. Friction is absent everywhere. The time taken by the block to reach from C to A is: (g = 10m/s2)

A

1.2 s

B

0.74 s

C

2.56 s

D

0.42 s

Answer

0.74 s

Explanation

Solution

arel = a0 cos q –g sin q

= g (cos q – sin q ) = g(32−12)\mathrm { g } \left( \frac { \sqrt { 3 } } { 2 } - \frac { 1 } { 2 } \right)

= 0.7322×g\frac { 0.732 } { 2 } \times \mathrm { g }

Srel = 12\frac { 1 } { 2 } arelt2

1m = 12\frac { 1 } { 2 } × 0.366 × g × t2 t=20.366×g\mathrm { t } = \sqrt { \frac { 2 } { 0.366 \times g } }