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Question: A block is lying on an inclined plane which makes 60° with the horizontal. If coefficient of frictio...

A block is lying on an inclined plane which makes 60° with the horizontal. If coefficient of friction between block and plane is 0.25 and g=10m/s2g = 10m/s^{2}, then acceleration of the block when it moves along the plane will be

A

2.50m/s22.50m/s^{2}

B

5.00m/s25.00m/s^{2}

C

7.4m/s27.4m/s^{2}

D

8.66m/s28.66m/s^{2}

Answer

7.4m/s27.4m/s^{2}

Explanation

Solution

a=g(sinθμcosθ)=10(sin600.25cos60)a = g(\sin\theta - \mu\cos\theta) = 10(\sin 60{^\circ} - 0.25\cos 60{^\circ})

a=7.46mum/s2a = 7.4\mspace{6mu} m/s^{2}