Solveeit Logo
Login

Question

Question: A block is kept on a smooth inclined plane of angle of inclination 30º that moves with a constant ac...

A block is kept on a smooth inclined plane of angle of inclination 30º that moves with a constant acceleration so that the block does not slide relative to the inclined plane. Let F1 be the contact force between the block and the plane. Now the inclined plane stops and let F2 be the contact force between the two in this case. Then F1/F2 is :

A

1

B

43\frac { 4 } { 3 }

C

2

D

32\frac { 3 } { 2 }

Answer

43\frac { 4 } { 3 }

Explanation

Solution

Surface is smooth. Therefore, force of friction between the block and the plane is zero. So, contact force is really the normal reaction between the two.

In the first case F1 sin 30º = ma

and F1 cos 300 = mg

or F1 =mgcos⁡30∘\frac { m g } { \cos 30 ^ { \circ } }

and in the second case

F2 = mg cos 300

\ == 43\frac { 4 } { 3 }