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Question

Physics Question on laws of motion

A block is kept on a frictionless inclined surface with angle of inclination 'α\alpha'. The incline is given an acceleration a to keep the block stationary. Then a is equal to :

A

g/tanαg/ tan\,\alpha

B

gcosecαg\,cosec\,\alpha

C

gg

D

gtanαg tan\,\alpha

Answer

gtanαg tan\,\alpha

Explanation

Solution

In the frame of wedge, the force diagram of block is shown in figure. From free body diagram of wedge. For block to remain stationary, macosα=mgsinαma\, cos\, \alpha = mg\, sin\, \alpha a=gtanαa=g\,tan \, \alpha