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Question: A block is hanged from spring in a cage. Elongation in spring is 'x<sub>1</sub>' and 'x<sub>2</sub>'...

A block is hanged from spring in a cage. Elongation in spring is 'x1' and 'x2' when cage moves up and down respectively with same acceleration. The expansion in spring when the cage move horizontally with same acceleration –

A

x1+x22\frac { x _ { 1 } + x _ { 2 } } { 2 }

B

x12x222\sqrt { \frac { x _ { 1 } ^ { 2 } - x _ { 2 } ^ { 2 } } { 2 } }

C

D

Answer

Explanation

Solution

x1 = (g + a)

x2 = (g – a)

x3 =

[m = mass of pendulum

k = spring constant]

\ = .2(g2 + a2)

=

̃ x3 =