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Question: A block is at rest on an inclined plane making an angle \(\alpha\) with the horizontal. As the ang...

A block is at rest on an inclined plane making an angle α\alpha with the horizontal. As the angle α\alpha of the incline is increased, the block starts slipping when the angle of inclination becomes θ\theta . The coefficient of static friction between the block and the surface of the inclined plane is or A body starts sliding down at an angle θ\theta to horizontal. Then coefficient of friction is equal to

A

sinθ\sin \theta

B

cosθ\cos \theta

C

tanθ\tan \theta

D

Independent of θ\theta

Answer

tanθ\tan \theta

Explanation

Solution

Coefficient of friction = Tangent of angle of repose

\therefore μ=tanθ\mu = \tan \theta