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Question

Physics Question on laws of motion

A block BB is pushed momentarily along a horizontal surface with an initial velocity vv . If μ\mu is the coefficient of sliding friction between BB and the surface, block BB will come to rest after a time

A

vgμ\frac{v}{g\mu }

B

gμv\frac{g\mu }{v}

C

gv\frac{g}{v}

D

vg\frac{v}{g}

Answer

vgμ\frac{v}{g\mu }

Explanation

Solution

Block BB will come to rest, if force applied to will vanish due to frictional force acting between block BB and surface, ie, force applied = frictional force
ie, μmg=ma\mu m g=m a
or μmg=m(vt)\mu m g=m\left(\frac{v}{t}\right)
or t=vμgt=\frac{v}{\mu g}