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Question

Physics Question on Inclined planes

A block 'A ' takes 2 s to slide down a frictionless incline of 30° and length 'l ', kept inside a lift going up with uniform velocity 'v '. If the incline is changed to 45°, the time taken by the block, to slide down the incline, will be approximately

A

2.66 s

B

0.83 s

C

1.68 s

D

0.70 s

Answer

1.68 s

Explanation

Solution

The correct answer is (C) : 1.68
θ1=30°,θ2=45°θ_1 = 30°, θ_2 = 45°
a1=gsinθ1=5m/s2,a2=gsinθ2a_1 = g\sinθ_1 = 5m/s^2, a_2 = g\sinθ_2
=52m/s2= 5\sqrt2m/s^2
t1t2=2la12la2=a2a1\frac{t_1}{t_2} = \frac{\sqrt{\frac{2l}{a_1}}}{\sqrt{\frac{2l}{a_2}}} = \sqrt{\frac{a_2}{a_1}}
t1t2=(2)14\frac{t_1}{t_2} = (2)^{\frac{1}{4}}
t2=(2)34t_2 = (2)^{\frac{3}{4}}
≈ 1.68s