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Question: A block A of mass M = 2kg is connected to another block B of mass 1 kg with a string and a spring of...

A block A of mass M = 2kg is connected to another block B of mass 1 kg with a string and a spring of force constant k = 600 N/m as shown in the figure. Initially spring is compressed to 10 cm and whole system is moving on a smooth surface with a velocity v = 1 m/s. At any time thread is burnt, the velocity of block A, when B is having maximum velocity w.r.t. ground, is –

A

Zero

B

1 m/s

C

3 m/s

D

None of these

Answer

Zero

Explanation

Solution

In CM frame : -

mvl = Mv2 ; vl = 2v2

from COE,

12\frac { 1 } { 2 } mv12\operatorname { mv } _ { 1 } ^ { 2 } + 12Mv22=12k02\frac { 1 } { 2 } \mathrm { Mv } _ { 2 } ^ { 2 } = \frac { 1 } { 2 } \mathrm { k } \ell _ { 0 } ^ { 2 } ̃ 2v22+v22=12k022 \mathrm { v } _ { 2 } ^ { 2 } + \mathrm { v } _ { 2 } ^ { 2 } = \frac { 1 } { 2 } \mathrm { k } \ell _ { 0 } ^ { 2 }

v2 = 0.1 × 10 = 1 m/s in –x direction

In ground frame

VM = – v2 + v = 0