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Question

Question: A black body radiates energy at the rate of ![](https://cdn.pureessence.tech/canvas_258.png?top_left...

A black body radiates energy at the rate of W/m2 at a high temperature TK. When the temperature is reduced to T2K\frac { T } { 2 } K , the radiant energy will be

A

E16\frac { E } { 16 }

B

E4\frac { E } { 4 }

C

D

16E16 E

Answer

E16\frac { E } { 16 }

Explanation

Solution

ET4E1E2=T4T4×24E2=E16E \propto T ^ { 4 } \Rightarrow \frac { E _ { 1 } } { E _ { 2 } } = \frac { T ^ { 4 } } { T ^ { 4 } } \times 2 ^ { 4 } \Rightarrow E _ { 2 } = \frac { E } { 16 }