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Question

Physics Question on thermal properties of matter

A black body is at a temperature of 5760K5760 \,K. The energy of radiation emitted by the body at wavelength 250nm250\,nm is U1U_1, at wavelength 500nm500\, nm is U2U_2 and that at 1000nm1000\,nm is U3U_3. Wien's constant, b=2.88×106nmKb = 2.88 \times 10^6 \, nm\,K. Which of the following is correct ?

A

U3=0U_3 = 0

B

U1>U2U_1 > U_2

C

U2>U1U_2 > U_1

D

U1=0U_1 = 0

Answer

U2>U1U_2 > U_1

Explanation

Solution

Maximum amount of emitted radiation corresponding to λm=bT\lambda_m = \frac{b}{T}
λm=2.88×106nmK5760K=500nm\lambda_m = \frac{2.88 \times 10^{6} \, nmK}{5760K} = 500 \, nm
From the graph U1<U2>U3U_1 < U_2 > U_3