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Question

Question: A black body at a temperature of \(227 ^ { \circ } \mathrm { C }\) radiates heat energy at the rate ...

A black body at a temperature of 227C227 ^ { \circ } \mathrm { C } radiates heat energy at the rate of 5 cal/cm2-sec. At a temperature of , the rate of heat radiated per unit area in cal/cm2will be

A

80

B

160

C

250

D

500

Answer

80

Explanation

Solution

E2E1=(T2T1)4\frac { E _ { 2 } } { E _ { 1 } } = \left( \frac { T _ { 2 } } { T _ { 1 } } \right) ^ { 4 } =(273+727237+227)=(1000)4(500)4=16E2=80= \left( \frac { 273 + 727 } { 237 + 227 } \right) = \frac { ( 1000 ) ^ { 4 } } { ( 500 ) ^ { 4 } } = 16 \Rightarrow E _ { 2 } = 80