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Question

Question: A black body at a temperature of 1640 K has the wavelength corresponding to maximum emission equal t...

A black body at a temperature of 1640 K has the wavelength corresponding to maximum emission equal to 1.75μ\mu. Assuming the moon to be a perfectly black body, the temperature of the moon, if the wavelength corresponding to maximum emission is 14.35 μ is

A

100 K

B

150 K

C

200 K

D

250 K

Answer

200 K

Explanation

Solution

T2T1=λm1λm2=1.7514.35T2=1.7514.35×1640=200 K\frac { T _ { 2 } } { T _ { 1 } } = \frac { \lambda _ { m _ { 1 } } } { \lambda _ { m _ { 2 } } } = \frac { 1.75 } { 14.35 } \Rightarrow T _ { 2 } = \frac { 1.75 } { 14.35 } \times 1640 = 200 \mathrm {~K}