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Question

Physics Question on thermal properties of matter

A black body at 13731373 ?? emits maximum energy corresponding to a wavelength of 1.781.78 microns. The temperature of the moon for which λm=14\lambda _{m}=14 micron would be

A

62.6?62.6?

B

58.9?-58.9?

C

63.7?-63.7?

D

64.2?64.2?

Answer

63.7?-63.7?

Explanation

Solution

T2T1=λm1λm2=1.7814\frac{T_{2}}{T_{1}}= \, \frac{\lambda _{m_{1}}}{\lambda _{m_{2}}}=\frac{1.78}{14} T2=1.7814×T1=1.7814(1373+273)T_{2}=\frac{1.78}{14} \, \times T_{1}=\frac{1.78}{14}\left(1373 + 273\right) =209.3K=209.3=209.3K=209.3 273=63.7?-273=-63.7?