Question

A bivalent metal has the equivalent weight of $12$. The molecular weight of its oxide will be

• A. 36
• B. 24
• C. 40
• D. 32

Answer 1

Answer: (C)

40

Answer 2

Atomic wt. of metal $=2 \times 12$ $=24$ $\therefore\,\,\,$ Mol. wt. of its oxide $=24+16$ $=40$