Question

A bivalent metal has an equivalent mass of $32$. The molecular mass of the metal nitrate is

• A. 192
• B. 188
• C. 182
• D. 168

Answer 1

Answer: (B)

188

Answer 2

Atomic mass of the metal $=32 \times 2=64$

Formula of metal nitrate $=M\left( NO _{3}\right)_{2}$
$\therefore$ Molecular mass $=64+28+96=188$