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Question

Physics Question on Motion in a straight line

A bird is tossing (flying to and fro) between two cars moving towards each other on a straight road. One car has speed of 27kmh127 \,km\, h^{-1} while the other has the speed of 18kmh118 \,km \,h^{-1} . The bird starts moving from first car towards the other and is moving with the speed of 36kmh136\, km \,h^{-1} when the two cars were separated by 36km36 \,km . The total distance covered by the bird is

A

28.8km28.8\,km

B

38.8km38.8\,km

C

48.8km48.8\,km

D

58.8km58.8\,km

Answer

28.8km28.8\,km

Explanation

Solution

Velocity of car AA , vA=+27kmh1v_A = + 27\, km \,h^{-1} Velocity of car BB , vB=18kmh1v_B = -18 \,km \,h^{-1} Relative velocity of car AA with respect to car BB =vAvB+27kmh1(18kmh1)=45kmh1=v_{A}-v_{B}+27\,km\,h^{-1}-\left(-18\,km\,h^{-1}\right)=45\,km\,h^{-1} Time taken by the two cars to meet =36km45kmh1=0.8h=\frac{36\,km}{45\,km\,h^{-1}}=0.8\,h Thus, distance covered by the bird =36kmh1×0.8h=28.8km= 36\, km\, h^{-1} \times 0.8\, h = 28.8 \,km