Question

A bird is sitting in a wire cage hanging from the spring balance. Let the reading of the spring balance be $W_{1}$. If the bird flies about inside the cage, the reading of the spring balance is $W_{2}$. Which of the following is true

• A. $W_{1} = W_{2}$
• B. $W_{1} > W_{2}$
• C. $W_{1} < W_{2}$
• D. Nothing definite can be predicted

Answer 1

Answer: (B)

$W_{1} > W_{2}$

Answer 2

In this problem the cage is wire-cage the momentum of the system will not be conserved and due to this the weight of the system will be lesser when the bird is flying as compared to the weight of the same system when bird is resting is $W_{2} < W_{1}$.