Question

A bird flying over a swimming pool at a height of 2m from the water surface. If the bottom is perfectly plane reflecting surface and depth of swimming pool is 1 m, then the distance of final image of bird from the bird itself is (m_W = 4/3) –

• A. $\frac { 11 } { 3 }$m
• B. $\frac { 23 } { 3 } \mathrm {~m}$
• C. $\frac { 11 } { 4 }$m
• D. $\frac { 11 } { 2 }$m

Answer 1

Answer: (D)

$\frac { 11 } { 2 }$m

Answer 2

AI₁ = AO × m_W = 2 × $\frac { 4 } { 3 }$= $\frac { 8 } { 3 }$m

on mirror (2) event take place

\ I₂ will be behind the mirror at distance of

$\frac { 8 } { 3 }$+ 1 = $\frac { 11 } { 3 }$ m

AI₃ = = $\frac { 1 + \frac { 11 } { 3 } } { \frac { 4 } { 3 } }$ = $\frac { 14 } { 4 }$ m

distance of final image from object O

= 2 + $\frac { 14 } { 4 }$ = $\frac { 22 } { 4 }$ = $\frac { 11 } { 2 }$ m