Question
Question: A bird flying at a height of 3.6m above the surface of water and a fish is in the water at a depth o...
A bird flying at a height of 3.6m above the surface of water and a fish is in the water at a depth of 1.2m. The apparent height of bird to the fish is (μwater=34)
A. 3.9m
B. 4.8m
B. 5.2m
D. 4.5m
Solution
A bird is flying at some height and the fish is under water at a certain depth. Water is a denser medium and air is a rarer medium. Therefore due to refraction, the image of the fish is raised.
Thus, the fish will appear to be closer to the bird. (Its depth will decrease). This decreased depth is the apparent depth.
Formula Used: The real depth and the apparent depth are related as: Apparent DepthReal Depth=μ
Complete step by step solution: It is given in the problem that a fish is in the water at a depth of 1.2m.
So the real depth of the fish will be 1.2m. Also, a bird is flying above water at some height. From the point of view of the bird, the fish will appear to be raised (closer than the real depth).This is known as the apparent depth of the fish. It happens because water is a denser medium as compared to air. The real depth and the apparent depth are related as
Apparent DepthReal Depth=μ →(1)
where, μ is the refractive index of water
Here, μ=34 and Real Depth=1.2m. Substituting in equation (1)