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Question: A Big Mac hamburger from McDonald's contains \( 540 \) calories. (a) How many kilojoules does a bi...

A Big Mac hamburger from McDonald's contains 540540 calories.
(a) How many kilojoules does a big Mac contain?
(b) For how many hours would the amount of energy in a big Mac light a 100100 watt light-bulb (1watt=1Js11watt = 1J{s^{ - 1}}).

Explanation

Solution

In the above question we have been given the content of the burger in the form of calories. Calorie is the unit of energy and it is smaller than that of joules. As per our knowledge we know that 1calorie=4.184J1calorie = 4.184J and we have to use this conversion to solve this problem.

Complete step by step answer:
Let us use the given information that the big Mac hamburger contains 540540 calories then
We have,
1calorie=4.184J1calorie = 4.184J
540calories=540×1calorie\therefore 540calories = 540 \times 1calorie
=540×4.184J= 540 \times 4.184J
=2259.36J= 2259.36J
We have been asked the content in the form of kilojoules
Now, we know that the 103grams=1kilo{10^3}grams = 1kilo
540calories=2.259×103J\therefore 540calories = 2.259 \times {10^3}J
=2.259kJ= 2.259kJ
Hence the big Mac contains 2.259kJ2.259kJ
Now, we have been asked about the time in hours the amount of energy in a big mac burger can light a 100100 watt light bulb.
Here, we already have found out how much energy a big Mac contains in the (a.) part of this question.
Energy =2.259kJ= 2.259kJ
1watt=1Js11watt = 1J{s^{ - 1}} 100watt=100Js1\Rightarrow 100watt = 100J{s^{ - 1}}
1hour=3600s1hour = 3600s
This is the given data and we have to make use of this data to find out the answer of this question.
Now, for hours (T)(T) taken to light the lightbulb is given as follows:
T=2.259J100Js1×1hour3600sT = \dfrac{{2.259J}}{{100J{s^{ - 1}}}} \times \dfrac{{1hour}}{{3600s}}
T=2.259J100Js1×1hour3600s\Rightarrow T = \dfrac{{2.259{J}}}{{100{J}{{{s}}^{ - 1}}}} \times \dfrac{{1hour}}{{3600{s}}}
On solving, this gives the answer as
T=6.276×103hours\Rightarrow T = 6.276 \times {10^{ - 3}}hours
Hence, the time to light up the bulb is 6.276×103hours6.276 \times {10^{ - 3}}hours with the energy that contains the Mac.

Note:
We must be careful about the conversion of the units as we did in the above answering procedure. It needs good calculation and conversion knowledge to do this type of problem. Energy, power, hour all are interdependent values and need to be aware about their units.