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Question

Physics Question on Polarisation

A beam of unpolarised light of intensity I0I_0 is passed through a polaroid A and then through another polaroid B which is oriented so that its principal plane makes an angle of 45° relative to that of A. The intensity of emergent light is:

A

I02\frac{I_0}{2}

B

I022\frac{I_0}{2\sqrt2}

C

I04\frac{I_0}{4}

D

I08\frac{I_0}{8}

Answer

I04\frac{I_0}{4}

Explanation

Solution

When unpolarised light passes through a polaroid, the intensity of the transmitted light II is given by:

I=I02,I = \frac{I_0}{2},

where I0I_0 is the intensity of the incident unpolarised light.

Passing through Polaroid A: After passing through polaroid A, the intensity becomes:

IA=I02.I_A = \frac{I_0}{2}.

Passing through Polaroid B: When the light passes through the second polaroid B at an angle θ=45\theta = 45^\circ relative to the first:

IB=IAcos2(45)=(I02)cos2(45).I_B = I_A \cos^2(45^\circ) = \left( \frac{I_0}{2} \right) \cos^2(45^\circ).

Since cos(45)=12\cos(45^\circ) = \frac{1}{\sqrt{2}}:

IB=(I02)(12)2=(I02)(12)=I04.I_B = \left( \frac{I_0}{2} \right) \left( \frac{1}{\sqrt{2}} \right)^2 = \left( \frac{I_0}{2} \right) \left( \frac{1}{2} \right) = \frac{I_0}{4}.

Thus, the intensity of emergent light after passing through both polaroids is:

I04.\frac{I_0}{4}.