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Question: A beam of light propagating in medium A with index of refraction n (1) passes across an interface in...

A beam of light propagating in medium A with index of refraction n (1) passes across an interface into medium B with index of refraction n(2). The angle of incidence is greater than the angle of refraction; v(1) and v(2) denotes the speed of light in A and B. Then which of the following is true

A

v(1) > v(2) and n(1) > n(2)

B

v(1) > v(2) and n(1) < n(2)

C

v(1) < v(2) and n(1) > n(2)

D

v(1) < v(2) and n(1) < n(2)

Answer

v(1) > v(2) and n(1) < n(2)

Explanation

Solution

∠ i > ∠ r, it means light ray is going from rarer medium (1) to denser medium.

So v(A)>v(B)v ( A ) > v ( B ) and n(A)<n(B)n ( A ) < n ( B )