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Question

Physics Question on single slit diffraction

A beam of light of wavelength 600 nm from a distant source falls on a single slit I mm wide and the resulting diffraction-pattern is observed on a screen 2m away. The distance between the first dark fringes on either side of the central bright fringe is

A

1.2 cm

B

1.2 mm

C

2.4cm

D

2.4mm

Answer

2.4mm

Explanation

Solution

β=λDd=600×109×21×103=12×104m\beta =\frac{\lambda D}{d}=\frac{600\times {{10}^{-9}}\times 2}{1\times {{10}^{-3}}}=12\times {{10}^{-4}}\,m So, distance between the first dark fringes on either side of the central bright fringe X=2βX=2\beta =2×12×104m=2\times 12\times {{10}^{-4}}m =24×104m=24\times {{10}^{-4}}m =2.4mm=2.4\,mm