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Question: A beam of length l lies on the + x-axis with its left end on the origin. A cable pulls the beam in y...

A beam of length l lies on the + x-axis with its left end on the origin. A cable pulls the beam in y – direction with a force F = F0(1xl)\left( 1 - \frac{x}{l} \right). If the axis is fixed at x = 0 then find the torque.

A

– F0l

B

F0l/2

C

– F0l/2

D

None of these

Answer

F0l/2

Explanation

Solution

Torque dτ = 0lFx=F0l2\int_{0}^{l}{Fx = \frac{F_{0}l}{2}}