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Question: A beam of length l lies on the +x axis with its left end on the origin. A cable pulls the beam in y-...

A beam of length l lies on the +x axis with its left end on the origin. A cable pulls the beam in y-direction with a force F = F0 (1xl)\left( 1–\frac{x}{\mathcal{l}} \right). If the axis is fixed at x = 0 then find the torque –

A

– F0l

B

F0l2\frac{F_{0}\mathcal{l}}{2}

C

F0l2\frac{F_{0}\mathcal{l}}{2}

D

None of these

Answer

F0l2\frac{F_{0}\mathcal{l}}{2}

Explanation

Solution

Torque t = dτ\int_{}^{}{d\tau} = 0lFx\int_{0}^{\mathcal{l}}{Fx} = F0l2\frac{F_{0}\mathcal{l}}{2}