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Question: A beam of ions with velocity \(5 \times 10 ^ { 7 } \mathrm { C } / \mathrm { kg }\), then the radius...

A beam of ions with velocity 5×107C/kg5 \times 10 ^ { 7 } \mathrm { C } / \mathrm { kg }, then the radius of the circular path described will be

A

0.10 m

B

0.16 m

C

0.20 m

D

0.25 m

Answer

0.10 m

Explanation

Solution

r=mvBqr = \frac { m v } { B q }