Question

A beaker of radius 6 cm is filled with mercury up to a height to 12 cm. Given that the density of mercury is $13600\text{ }kg/{{m}^{3}},$ the force exerted by the mercury on the bottom of the beaker is approximately.

• A. 184 N
• B. 1100N
• C. 1200 N
• D. 1300 N

Answer 1

Answer: (A)

184 N

Answer 2

: Pressure of mercury on bottom $=dgh$ $P=13600\times 10\times \frac{12}{100}N{{m}^{-2}}$ Area of bottom $=\pi {{R}^{2}}=3.14\times {{\left( \frac{6}{100} \right)}^{2}}{{m}^{2}}$ $\therefore$ Force = Pressure $\times$ area or Force $=\frac{13600\times 10\times 12\times 3.14\times 36}{100\times 100\times 100}N$ or Force = 184.48 N.