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Question: A battery of e.m.f. 3 volt and internal resistance 1.0 ohm is connected in series with copper voltam...

A battery of e.m.f. 3 volt and internal resistance 1.0 ohm is connected in series with copper voltameter. The current flowing in the circuit is 1.5 amperes. The resistance of voltameter will be

A

Zero

B

1.0 ohm

C

1.5 ohm

D

2.0 ohm

Answer

1.0 ohm

Explanation

Solution

3=1.5(1+r)3 = 1.5(1 + r)r = 1Ω